Making the necessary substitutions and evaluating "a":
2X.0833 a (.01257
Since it is assumed that the deceleration period is the same as the acceleration period, the value of the deceleration will also be 1066 feet per second per second. This is a high value and is equivalent to approximately 33 times the normal acceleration of gravity. An idea of the magnitude of the force required to produce this acceleration can be had by assuming that the equivalent mass subjected to the acceleration is 50 pounds in weight.
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